What is the inverse of f(x)=(4x-3)/(2x+1) ?

The inverse of f(x)=(4x-3)/(2x+1) is (-3-x)/(2(-2+x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(4x-3)/(2x+1)

inverse

f (x) = \frac{4 x - 3}{2 x + 1}

\frac{- 3 - x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 3}{2 x + 1}

Replace

x

with

y

x = \frac{4 y - 3}{2 y + 1}

Solve for

y, x = \frac{4 y - 3}{2 y + 1}

\frac{- 3 - x}{2 ( - 2 + x )}

f (x) = 4 - x + 2

- 2 x^{3} + 1

f (x) = x^{2} + x - 2

f (x) = x - 2 + 6

arccos (- \frac{3}{2})

What is the inverse of f(x)=(4x-3)/(2x+1) ?
The inverse of f(x)=(4x-3)/(2x+1) is (-3-x)/(2(-2+x))