What is the inverse of f(x)= 1/4 (4x)^2 ?

The inverse of f(x)= 1/4 (4x)^2 is (sqrt(x))/2 ,-(sqrt(x))/2

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inverse of f(x)= 1/4 (4x)^2

inverse

f (x) = \frac{1}{4} (4 x)^{2}

\frac{x}{2}, - \frac{x}{2}

Solution steps

y = \frac{1}{4} (4 x)^{2}

Replace

x

with

y

x = \frac{1}{4} (4 y)^{2}

Solve for

y, x = \frac{1}{4} (4 y)^{2}

\frac{x}{2}, - \frac{x}{2}

f (x) = - \frac{1}{4} x - \frac{13}{4}

f (x) = x^{2} - 3 x + 1

f (x) = x^{2} - 3 x + 5

5 - x + 3

- 3 x + 7

What is the inverse of f(x)= 1/4 (4x)^2 ?
The inverse of f(x)= 1/4 (4x)^2 is (sqrt(x))/2 ,-(sqrt(x))/2