What is the inverse of f(x)=2(x-5)^2 ?

The inverse of f(x)=2(x-5)^2 is sqrt(x/2)+5,-sqrt(x/2)+5

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inverse of f(x)=2(x-5)^2

inverse

f (x) = 2 (x - 5)^{2}

\frac{x}{2} + 5, - \frac{x}{2} + 5

Solution steps

y = 2 (x - 5)^{2}

Replace

x

with

y

x = 2 (y - 5)^{2}

Solve for

y, x = 2 (y - 5)^{2}

\frac{x}{2} + 5, - \frac{x}{2} + 5

- 2 (x + 3)^{3}

f (x) = 8 (\frac{x + 10}{9})^{\frac{1}{7}}

f (x) = \frac{1}{9} x^{2}

lo g_{10} (x - 4) + 2

f (y) = 2 y - y^{2}

What is the inverse of f(x)=2(x-5)^2 ?
The inverse of f(x)=2(x-5)^2 is sqrt(x/2)+5,-sqrt(x/2)+5