What is the inverse of f(x)=8x^2+3 ?

The inverse of f(x)=8x^2+3 is (sqrt(2)sqrt(x-3))/4 ,-(sqrt(2)sqrt(x-3))/4

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inverse of f(x)=8x^2+3

inverse

f (x) = 8 x^{2} + 3

\frac{2 x - 3}{4}, - \frac{2 x - 3}{4}

Solution steps

y = 8 x^{2} + 3

Replace

x

with

y

x = 8 y^{2} + 3

Solve for

y, x = 8 y^{2} + 3

\frac{2 x - 3}{4}, - \frac{2 x - 3}{4}

f (x) = x + \frac{1}{x}, x > 0

4 + x + 9

f (x) = \frac{( x + 4 )}{x - 5}

g (x) = 4 x^{2} + 8

What is the inverse of f(x)=8x^2+3 ?
The inverse of f(x)=8x^2+3 is (sqrt(2)sqrt(x-3))/4 ,-(sqrt(2)sqrt(x-3))/4