What is the inverse of f(x)=(x-8)^2+1 ?

The inverse of f(x)=(x-8)^2+1 is sqrt(x-1)+8,-sqrt(x-1)+8

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inverse of f(x)=(x-8)^2+1

inverse

f (x) = (x - 8)^{2} + 1

x - 1 + 8, - x - 1 + 8

Solution steps

y = (x - 8)^{2} + 1

Replace

x

with

y

x = (y - 8)^{2} + 1

Solve for

y, x = (y - 8)^{2} + 1

x - 1 + 8, - x - 1 + 8

2^{x + 3} - 5

g (x) = 4 x^{2} - 12

f (x) = \frac{2 - x}{2 + x}

f (x) = \frac{- 7}{8 + 3 x}

arcsin (\frac{2}{2})

What is the inverse of f(x)=(x-8)^2+1 ?
The inverse of f(x)=(x-8)^2+1 is sqrt(x-1)+8,-sqrt(x-1)+8