What is the inverse of f(x)=x(x+1) ?

The inverse of f(x)=x(x+1) is (-1+sqrt(1+4x))/2 ,(-1-sqrt(1+4x))/2

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inverse of f(x)=x(x+1)

inverse

f (x) = x (x + 1)

\frac{- 1 + 1 + 4 x}{2}, \frac{- 1 - 1 + 4 x}{2}

Solution steps

y = x (x + 1)

Replace

x

with

y

x = y (y + 1)

Solve for

y, x = y (y + 1)

\frac{- 1 + 1 + 4 x}{2}, \frac{- 1 - 1 + 4 x}{2}

\frac{x}{x - 3}

g (x) = e^{x + 1}

\frac{1}{x ^{2} + 1}

f (x) = lo g_{10} (2 x)

f (x) = - 1 + x, x \geq 1

What is the inverse of f(x)=x(x+1) ?
The inverse of f(x)=x(x+1) is (-1+sqrt(1+4x))/2 ,(-1-sqrt(1+4x))/2