What is the inverse of f(x)=3(x-4)^2+5 ?

The inverse of f(x)=3(x-4)^2+5 is sqrt((x-5)/3)+4,-sqrt((x-5)/3)+4

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inverse of f(x)=3(x-4)^2+5

inverse

f (x) = 3 (x - 4)^{2} + 5

\frac{x - 5}{3} + 4, - \frac{x - 5}{3} + 4

Solution steps

y = 3 (x - 4)^{2} + 5

Replace

x

with

y

x = 3 (y - 4)^{2} + 5

Solve for

y, x = 3 (y - 4)^{2} + 5

\frac{x - 5}{3} + 4, - \frac{x - 5}{3} + 4

f (x) = \frac{1}{6} lo g_{3} (- 3 x) + 2

f (x) = 0. 8^{x}

f (x) = \frac{2}{n} + 2

f (x) = \frac{5 x + 8}{- 3 x - 1}

What is the inverse of f(x)=3(x-4)^2+5 ?
The inverse of f(x)=3(x-4)^2+5 is sqrt((x-5)/3)+4,-sqrt((x-5)/3)+4