What is the inverse of 3(x-2)^2-4 ?

The inverse of 3(x-2)^2-4 is sqrt((x+4)/3)+2,-sqrt((x+4)/3)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 3(x-2)^2-4

inverse

3 (x - 2)^{2} - 4

\frac{x + 4}{3} + 2, - \frac{x + 4}{3} + 2

Solution steps

y = 3 (x - 2)^{2} - 4

Replace

x

with

y

x = 3 (y - 2)^{2} - 4

Solve for

y, x = 3 (y - 2)^{2} - 4

\frac{x + 4}{3} + 2, - \frac{x + 4}{3} + 2

f (x) = \frac{6}{x - 2}

f (x) = \frac{6}{x - 4}

f (x) = \frac{- 16 a + 5}{3}

f (x) = 2 lo g_{10} (x) - 5

f (x) = arcsin (\frac{1}{x ^{2} + 1})

What is the inverse of 3(x-2)^2-4 ?
The inverse of 3(x-2)^2-4 is sqrt((x+4)/3)+2,-sqrt((x+4)/3)+2