What is the inverse of f(x)=-2(x+3)^2+1 ?

The inverse of f(x)=-2(x+3)^2+1 is sqrt(-(x-1)/2)-3,-sqrt(-(x-1)/2)-3

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inverse of f(x)=-2(x+3)^2+1

inverse

f (x) = - 2 (x + 3)^{2} + 1

- \frac{x - 1}{2} - 3, - - \frac{x - 1}{2} - 3

Solution steps

y = - 2 (x + 3)^{2} + 1

Replace

x

with

y

x = - 2 (y + 3)^{2} + 1

Solve for

y, x = - 2 (y + 3)^{2} + 1

- \frac{x - 1}{2} - 3, - - \frac{x - 1}{2} - 3

f (x) = x + 2 - 8

f (x) = 2^{x} - 2

f (x) = 2^{(x + 1)} - 3

f (x) = \frac{x ^{3} - 4}{x ^{3} - 5}

\frac{3 x}{x ^{2} - 1}

What is the inverse of f(x)=-2(x+3)^2+1 ?
The inverse of f(x)=-2(x+3)^2+1 is sqrt(-(x-1)/2)-3,-sqrt(-(x-1)/2)-3