What is the inverse of f(x)=(4x^3)/5-7/6 ?

The inverse of f(x)=(4x^3)/5-7/6 is (3^{2/3}\sqrt[3]{30x+35})/6

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inverse of f(x)=(4x^3)/5-7/6

inverse

f (x) = \frac{4 x ^{3}}{5} - \frac{7}{6}

Solution steps

y = \frac{4 x ^{3}}{5} - \frac{7}{6}

Replace

x

with

y

x = \frac{4 y ^{3}}{5} - \frac{7}{6}

Solve for

y, x = \frac{4 y ^{3}}{5} - \frac{7}{6}

f (x) = \frac{1}{2} x^{2} + 2

f (x) = \frac{2 x + 3}{3 x - 7}

cos (0)

f (x) = ln (3 x - 8) - ln (x) + 2

f (x) = \frac{1}{9 - x - 3}

What is the inverse of f(x)=(4x^3)/5-7/6 ?
The inverse of f(x)=(4x^3)/5-7/6 is (3^{2/3}\sqrt[3]{30x+35})/6