What is the inverse of f(x)=((x+3))/((x-1)) ?

The inverse of f(x)=((x+3))/((x-1)) is (3+x)/(x-1)

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inverse of f(x)=((x+3))/((x-1))

inverse

f (x) = \frac{( x + 3 )}{( x - 1 )}

\frac{3 + x}{x - 1}

Solution steps

y = \frac{x + 3}{x - 1}

Replace

x

with

y

x = \frac{y + 3}{y - 1}

Solve for

y, x = \frac{y + 3}{y - 1}

\frac{3 + x}{x - 1}

x + 1 - 2

f (x) = 3 (x + 5)^{2}

f (x) = lo g_{2} (2 x - 4)

- 2 x^{3}

What is the inverse of f(x)=((x+3))/((x-1)) ?
The inverse of f(x)=((x+3))/((x-1)) is (3+x)/(x-1)