What is the inverse of f(x)=log_{10}(3x^4-9) ?

The inverse of f(x)=log_{10}(3x^4-9) is \sqrt[4]{(10^x+9)/3},-\sqrt[4]{(10^x+9)/3}

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inverse of f(x)=log_{10}(3x^4-9)

inverse

f (x) = lo g_{10} (3 x^{4} - 9)

Solution steps

y = lo g_{10} (3 x^{4} - 9)

Replace

x

with

y

x = lo g_{10} (3 y^{4} - 9)

Solve for

y, x = lo g_{10} (3 y^{4} - 9)

y = \frac{x + 1}{3}

f (x) = - 6 x + 2

h (x) = arcsin (x)

f (x) = 3 x + 7

f (x) = 3 x + 3

What is the inverse of f(x)=log_{10}(3x^4-9) ?
The inverse of f(x)=log_{10}(3x^4-9) is \sqrt[4]{(10^x+9)/3},-\sqrt[4]{(10^x+9)/3}