What is the inverse of f(x)=3-log_{2}(4+x) ?

The inverse of f(x)=3-log_{2}(4+x) is 2^{3-x}-4

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inverse of f(x)=3-log_{2}(4+x)

inverse

f (x) = 3 - lo g_{2} (4 + x)

2^{3 - x} - 4

Solution steps

y = 3 - lo g_{2} (4 + x)

Replace

x

with

y

x = 3 - lo g_{2} (4 + y)

Solve for

y, x = 3 - lo g_{2} (4 + y)

2^{3 - x} - 4

y = \frac{2 x + 4}{x - 3}

f (x) = \frac{5}{3} x - 15

y = (x - 2)^{3} + 1

f (x) = (x - 11)^{3} - 12

What is the inverse of f(x)=3-log_{2}(4+x) ?
The inverse of f(x)=3-log_{2}(4+x) is 2^{3-x}-4