What is the inverse of f(x)=(x^{1/3}-1)/9 ?

The inverse of f(x)=(x^{1/3}-1)/9 is 729x^3+243x^2+27x+1

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inverse of f(x)=(x^{1/3}-1)/9

inverse

f (x) = \frac{x ^{\frac{1}{3}} - 1}{9}

729 x^{3} + 243 x^{2} + 27 x + 1

Solution steps

y = \frac{x ^{\frac{1}{3}} - 1}{9}

Replace

x

with

y

x = \frac{y ^{\frac{1}{3}} - 1}{9}

Solve for

y, x = \frac{y ^{\frac{1}{3}} - 1}{9}

729 x^{3} + 243 x^{2} + 27 x + 1

2 - 3

f (x) = \frac{( x - 10 )}{5 x}

\frac{z}{z - 5}

f (x) = - 2 x^{2} + 2

What is the inverse of f(x)=(x^{1/3}-1)/9 ?
The inverse of f(x)=(x^{1/3}-1)/9 is 729x^3+243x^2+27x+1