What is the inverse of f(t)=30-30e^{-ln(10)*t} ?

The inverse of f(t)=30-30e^{-ln(10)*t} is -(ln(-\frac{t-30)/(30))}{ln(10)}

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inverse of f(t)=30-30e^{-ln(10)*t}

inverse

f (t) = 30 - 30 e^{- l n (10) \cdot t}

- \frac{ln ( - \frac{t - 30}{30} )}{ln ( 10 )}

Solution steps

y = 30 - 30 e^{- l n (10) t}

Replace

t

with

y

t = 30 - 30 e^{- l n (10) y}

Solve for

y, t = 30 - 30 e^{- l n (10) \cdot y}

- \frac{ln ( - \frac{t - 30}{30} )}{ln ( 10 )}

f (x) = \frac{3 x}{x ^{2} - 9}

R (q) = ln (1 + 10 q^{2})

f (x) = - x + 4 + 3

- 7 a + 5

What is the inverse of f(t)=30-30e^{-ln(10)*t} ?
The inverse of f(t)=30-30e^{-ln(10)*t} is -(ln(-\frac{t-30)/(30))}{ln(10)}