What is the inverse of f(x)=sqrt(((2x-3)/(x+1)+1)) ?

The inverse of f(x)=sqrt(((2x-3)/(x+1)+1)) is (-x^2-2)/(x^2-3)

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inverse of f(x)=sqrt(((2x-3)/(x+1)+1))

inverse

f (x) = (\frac{2 x - 3}{x + 1} + 1)

\frac{- x ^{2} - 2}{x ^{2} - 3}

Solution steps

y = \frac{2 x - 3}{x + 1} + 1

Replace

x

with

y

x = \frac{2 y - 3}{y + 1} + 1

Solve for

y, x = \frac{2 y - 3}{y + 1} + 1

\frac{- x ^{2} - 2}{x ^{2} - 3}

f (x) = lo g_{4} (x^{2}) + 1

f (x) = \frac{3}{x - 2}

f (x) = lo g_{10} (x - 4) + 2

f (x) = 5 x + 3 - 2

What is the inverse of f(x)=sqrt(((2x-3)/(x+1)+1)) ?
The inverse of f(x)=sqrt(((2x-3)/(x+1)+1)) is (-x^2-2)/(x^2-3)