What is the inverse of f(x)=sqrt(x^2+9) ?

The inverse of f(x)=sqrt(x^2+9) is sqrt(x^2-9),-sqrt(x^2-9)

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inverse of f(x)=sqrt(x^2+9)

inverse

f (x) = x^{2} + 9

x^{2} - 9, - x^{2} - 9

Solution steps

y = x^{2} + 9

Replace

x

with

y

x = y^{2} + 9

Solve for

y, x = y^{2} + 9

x^{2} - 9, - x^{2} - 9

f (x) = \frac{( x - 3 )}{2 x + 1}

f (x) = (x - 5)^{3} + 8

\frac{5 - 3 ^{x}}{2}

f (x) = x^{2} + 24 x + 144

What is the inverse of f(x)=sqrt(x^2+9) ?
The inverse of f(x)=sqrt(x^2+9) is sqrt(x^2-9),-sqrt(x^2-9)