What is the inverse of f(x)=-2(x-2)^2+8 ?

The inverse of f(x)=-2(x-2)^2+8 is sqrt(-(x-8)/2)+2,-sqrt(-(x-8)/2)+2

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inverse of f(x)=-2(x-2)^2+8

inverse

f (x) = - 2 (x - 2)^{2} + 8

- \frac{x - 8}{2} + 2, - - \frac{x - 8}{2} + 2

Solution steps

y = - 2 (x - 2)^{2} + 8

Replace

x

with

y

x = - 2 (y - 2)^{2} + 8

Solve for

y, x = - 2 (y - 2)^{2} + 8

- \frac{x - 8}{2} + 2, - - \frac{x - 8}{2} + 2

f (x) = \frac{3 x + 1}{x - 4}

f (x) = (x + 6)^{2}, x \geq - 6

f (x) = \frac{x + 8}{2}

f (x) = \frac{1}{3} (x - 1)

y = - 3 x - 3

What is the inverse of f(x)=-2(x-2)^2+8 ?
The inverse of f(x)=-2(x-2)^2+8 is sqrt(-(x-8)/2)+2,-sqrt(-(x-8)/2)+2