What is the inverse of f(x)=(x+6)^2,x>=-6 ?

The inverse of f(x)=(x+6)^2,x>=-6 is sqrt(x)-6,-sqrt(x)-6

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inverse of f(x)=(x+6)^2,x>=-6

inverse

f (x) = (x + 6)^{2}, x \geq - 6

x - 6, - x - 6

Solution steps

y = (x + 6)^{2}

Replace

x

with

y

x = (y + 6)^{2}

Solve for

y, x = (y + 6)^{2}

x - 6, - x - 6

f (x) = \frac{x + 8}{2}

f (x) = \frac{1}{3} (x - 1)

y = - 3 x - 3

f (x) = 2 x^{2} + 4 x + 12

f (x) = \frac{5}{7} x - 2

What is the inverse of f(x)=(x+6)^2,x>=-6 ?
The inverse of f(x)=(x+6)^2,x>=-6 is sqrt(x)-6,-sqrt(x)-6