What is the inverse of f(x)= 1/4 (x-6)^2-5,x<= 6 ?

The inverse of f(x)= 1/4 (x-6)^2-5,x<= 6 is 2sqrt(x+5)+6,-2sqrt(x+5)+6

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inverse of f(x)= 1/4 (x-6)^2-5,x<= 6

inverse

f (x) = \frac{1}{4} (x - 6)^{2} - 5, x \leq 6

2 x + 5 + 6, - 2 x + 5 + 6

Solution steps

y = \frac{1}{4} (x - 6)^{2} - 5

Replace

x

with

y

x = \frac{1}{4} (y - 6)^{2} - 5

Solve for

y, x = \frac{1}{4} (y - 6)^{2} - 5

2 x + 5 + 6, - 2 x + 5 + 6

f (x) = \frac{x + 1}{2 x}

f (x) = \frac{x ^{3}}{3}

\frac{2 ^{x}}{1 + 2 ^{x}}

f (x) = 7 x + 10

What is the inverse of f(x)= 1/4 (x-6)^2-5,x<= 6 ?
The inverse of f(x)= 1/4 (x-6)^2-5,x<= 6 is 2sqrt(x+5)+6,-2sqrt(x+5)+6