What is the inverse of f(x)=(x^2)/2-x-1 ?

The inverse of f(x)=(x^2)/2-x-1 is 1+sqrt(2x+3),1-sqrt(2x+3)

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inverse of f(x)=(x^2)/2-x-1

inverse

f (x) = \frac{x ^{2}}{2} - x - 1

1 + 2 x + 3, 1 - 2 x + 3

Solution steps

y = \frac{x ^{2}}{2} - x - 1

Replace

x

with

y

x = \frac{y ^{2}}{2} - y - 1

Solve for

y, x = \frac{y ^{2}}{2} - y - 1

1 + 2 x + 3, 1 - 2 x + 3

f (x) = 2.5 x + 11.5

f (x) = lo g_{5} (x - 2)

e^{y}

\frac{x + 28}{x - 7}

f (x) = lo g_{10} (\frac{x}{1 - x})

What is the inverse of f(x)=(x^2)/2-x-1 ?
The inverse of f(x)=(x^2)/2-x-1 is 1+sqrt(2x+3),1-sqrt(2x+3)