What is the inverse of f(x)=2x^2+3x-1 ?

The inverse of f(x)=2x^2+3x-1 is (-3+sqrt(8x+17))/4 ,(-3-sqrt(8x+17))/4

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inverse of f(x)=2x^2+3x-1

inverse

f (x) = 2 x^{2} + 3 x - 1

\frac{- 3 + 8 x + 17}{4}, \frac{- 3 - 8 x + 17}{4}

Solution steps

y = 2 x^{2} + 3 x - 1

Replace

x

with

y

x = 2 y^{2} + 3 y - 1

Solve for

y, x = 2 y^{2} + 3 y - 1

\frac{- 3 + 8 x + 17}{4}, \frac{- 3 - 8 x + 17}{4}

+ 5 x + 3

cos (1)

X

f (x) = (x - 20)^{2}, [20, \infty]

f (x) = \frac{10}{x} + 2

What is the inverse of f(x)=2x^2+3x-1 ?
The inverse of f(x)=2x^2+3x-1 is (-3+sqrt(8x+17))/4 ,(-3-sqrt(8x+17))/4