What is the inverse of f(x)=sqrt(13-x^2) ?

The inverse of f(x)=sqrt(13-x^2) is sqrt(-x^2+13),-sqrt(-x^2+13)

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inverse of f(x)=sqrt(13-x^2)

inverse

f (x) = 13 - x^{2}

- x^{2} + 13, - - x^{2} + 13

Solution steps

y = 13 - x^{2}

Replace

x

with

y

x = 13 - y^{2}

Solve for

y, x = 13 - y^{2}

- x^{2} + 13, - - x^{2} + 13

f (x) = \frac{x + 3}{7}

f (x) = \frac{1}{3} (5)^{- 2 (x + 4)} - 1

f (x) = - 2 (x + 1)^{2} - 4

f (x) = (x - 2)^{2} + 6

2 \cdot 5^{x} - 8

What is the inverse of f(x)=sqrt(13-x^2) ?
The inverse of f(x)=sqrt(13-x^2) is sqrt(-x^2+13),-sqrt(-x^2+13)