What is the inverse of f(x)=-2(x+1)^2-4 ?

The inverse of f(x)=-2(x+1)^2-4 is sqrt(-(x+4)/2)-1,-sqrt(-(x+4)/2)-1

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inverse of f(x)=-2(x+1)^2-4

inverse

f (x) = - 2 (x + 1)^{2} - 4

- \frac{x + 4}{2} - 1, - - \frac{x + 4}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} - 4

Replace

x

with

y

x = - 2 (y + 1)^{2} - 4

Solve for

y, x = - 2 (y + 1)^{2} - 4

- \frac{x + 4}{2} - 1, - - \frac{x + 4}{2} - 1

f (x) = (x - 2)^{2} + 6

2 \cdot 5^{x} - 8

- 2 x - 3

f (x) = - 2 x + 11 + 12

y = \frac{5}{3 ( x + 2 )} - 8

What is the inverse of f(x)=-2(x+1)^2-4 ?
The inverse of f(x)=-2(x+1)^2-4 is sqrt(-(x+4)/2)-1,-sqrt(-(x+4)/2)-1