What is the inverse of g(x)=2(x-1)^2-3 ?

The inverse of g(x)=2(x-1)^2-3 is sqrt((x+3)/2)+1,-sqrt((x+3)/2)+1

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inverse of g(x)=2(x-1)^2-3

inverse

g (x) = 2 (x - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

Solution steps

y = 2 (x - 1)^{2} - 3

Replace

x

with

y

x = 2 (y - 1)^{2} - 3

Solve for

y, x = 2 (y - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

2 cos (4 x - π)

f (x) = 2 x^{2} - 8 x + 5

f (x) = 2 + 6 + 7 x

h (x) = \frac{x + 1}{x - 2}

f (x) = \frac{5 x}{x + 4}

What is the inverse of g(x)=2(x-1)^2-3 ?
The inverse of g(x)=2(x-1)^2-3 is sqrt((x+3)/2)+1,-sqrt((x+3)/2)+1