What is the inverse of sqrt(x^2+2x) ?

The inverse of sqrt(x^2+2x) is -1+sqrt(x^2+1),-sqrt(x^2+1)-1

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inverse of sqrt(x^2+2x)

inverse

x^{2} + 2 x

- 1 + x^{2} + 1, - x^{2} + 1 - 1

Solution steps

y = x^{2} + 2 x

Replace

x

with

y

x = y^{2} + 2 y

Solve for

y, x = y^{2} + 2 y

- 1 + x^{2} + 1, - x^{2} + 1 - 1

x^{2} - 12 x + 11

f (x) = \frac{3}{5} x - \frac{3}{2}

f (x) = - x^{2} + 8 x

f (x) = 2 x^{2} - 28 x + 98

What is the inverse of sqrt(x^2+2x) ?
The inverse of sqrt(x^2+2x) is -1+sqrt(x^2+1),-sqrt(x^2+1)-1