What is the inverse of f(x)=2x^2-28x+98 ?

The inverse of f(x)=2x^2-28x+98 is (14+sqrt(2)sqrt(x))/2 ,(14-sqrt(2)sqrt(x))/2

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inverse of f(x)=2x^2-28x+98

inverse

f (x) = 2 x^{2} - 28 x + 98

\frac{14 + 2 x}{2}, \frac{14 - 2 x}{2}

Solution steps

y = 2 x^{2} - 28 x + 98

Replace

x

with

y

x = 2 y^{2} - 28 y + 98

Solve for

y, x = 2 y^{2} - 28 y + 98

\frac{14 + 2 x}{2}, \frac{14 - 2 x}{2}

f (x) = 7^{3 x - 5}

\frac{7 x + 9}{x + 7}

f (x) = lo g_{10} (x^{2})

y = x + 1

f (x) = \frac{- 2}{x - 5}

What is the inverse of f(x)=2x^2-28x+98 ?
The inverse of f(x)=2x^2-28x+98 is (14+sqrt(2)sqrt(x))/2 ,(14-sqrt(2)sqrt(x))/2