What is the inverse of f(x)=log_{10}(x^2) ?

The inverse of f(x)=log_{10}(x^2) is sqrt(10^x),-sqrt(10^x)

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inverse of f(x)=log_{10}(x^2)

inverse

f (x) = lo g_{10} (x^{2})

1 0^{x}, - 1 0^{x}

Solution steps

y = lo g_{10} (x^{2})

Replace

x

with

y

x = lo g_{10} (y^{2})

Solve for

y, x = lo g_{10} (y^{2})

1 0^{x}, - 1 0^{x}

y = x + 1

f (x) = \frac{- 2}{x - 5}

f (x) = lo g_{\frac{1}{2}} (x)

f (x) = 2 x^{2} + 13

f (x) = (x + 18)^{3}

What is the inverse of f(x)=log_{10}(x^2) ?
The inverse of f(x)=log_{10}(x^2) is sqrt(10^x),-sqrt(10^x)