What is the inverse of f(x)=x^2-6x+5,[3,+infinity ] ?

The inverse of f(x)=x^2-6x+5,[3,+infinity ] is 3+sqrt(x+4),3-sqrt(x+4)

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inverse of f(x)=x^2-6x+5,[3,+infinity ]

inverse

f (x) = x^{2} - 6 x + 5, [3, + \infty]

3 + x + 4, 3 - x + 4

Solution steps

y = x^{2} - 6 x + 5

Replace

x

with

y

x = y^{2} - 6 y + 5

Solve for

y, x = y^{2} - 6 y + 5

3 + x + 4, 3 - x + 4

f (x) = \frac{x ^{3} + 3}{2}

f (x) = 2 (\frac{1}{2} (x - 3))^{2} + 4

f (x) = \frac{( 1 - x )}{( 1 + x )}

f (x) = \frac{- 6 x - 3}{- 10 x + 8}

What is the inverse of f(x)=x^2-6x+5,[3,+infinity ] ?
The inverse of f(x)=x^2-6x+5,[3,+infinity ] is 3+sqrt(x+4),3-sqrt(x+4)