What is the inverse of 4x^2-x+17 ?

The inverse of 4x^2-x+17 is (1+sqrt(16x-271))/8 ,(1-sqrt(16x-271))/8

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inverse of 4x^2-x+17

inverse

4 x^{2} - x + 17

\frac{1 + 16 x - 271}{8}, \frac{1 - 16 x - 271}{8}

Solution steps

y = 4 x^{2} - x + 17

Replace

x

with

y

x = 4 y^{2} - y + 17

Solve for

y, x = 4 y^{2} - y + 17

\frac{1 + 16 x - 271}{8}, \frac{1 - 16 x - 271}{8}

f (x) = \frac{2 y - 5}{3 y}

f (x) = (x + 7)^{3} - 13

f (x) = 3 + 2 ln (x + b)

f (x) = \frac{9 x ^{2} + 12}{2}

What is the inverse of 4x^2-x+17 ?
The inverse of 4x^2-x+17 is (1+sqrt(16x-271))/8 ,(1-sqrt(16x-271))/8