What is the inverse of 2/(s^2+6s+8) ?

The inverse of 2/(s^2+6s+8) is (-3s+sqrt(s(s+2)))/s ,-(3s+sqrt(s(s+2)))/s

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inverse of 2/(s^2+6s+8)

inverse

\frac{2}{s ^{2} + 6 s + 8}

\frac{- 3 s + s ( s + 2 )}{s}, - \frac{3 s + s ( s + 2 )}{s}

Solution steps

y = \frac{2}{s ^{2} + 6 s + 8}

Replace

s

with

y

s = \frac{2}{y ^{2} + 6 y + 8}

Solve for

y, s = \frac{2}{y ^{2} + 6 y + 8}

\frac{- 3 s + s ( s + 2 )}{s}, - \frac{3 s + s ( s + 2 )}{s}

f (x) = - \frac{1}{3 x}

f (x) = \frac{( 2 x + 1 )}{( x - 3 )}

f (x) = \frac{( 2 x )}{( 3 x - 1 )}

f (x) = - \frac{5}{2} x + \frac{25}{2}

2 x^{3} + 9

What is the inverse of 2/(s^2+6s+8) ?
The inverse of 2/(s^2+6s+8) is (-3s+sqrt(s(s+2)))/s ,-(3s+sqrt(s(s+2)))/s