What is the inverse of f(x)=((2x+5))/((x-7)) ?

The inverse of f(x)=((2x+5))/((x-7)) is (5+7x)/(x-2)

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inverse of f(x)=((2x+5))/((x-7))

inverse

f (x) = \frac{( 2 x + 5 )}{( x - 7 )}

\frac{5 + 7 x}{x - 2}

Solution steps

y = \frac{2 x + 5}{x - 7}

Replace

x

with

y

x = \frac{2 y + 5}{y - 7}

Solve for

y, x = \frac{2 y + 5}{y - 7}

\frac{5 + 7 x}{x - 2}

f (x) = \frac{2 ( x - 1 )}{81}

f (x) = \frac{2}{3} x - 1 + 12

x + 3 - 5

f (x) = 5 x^{2} - 10 x + 7

y = \frac{b x + 3}{3 x - 7}

What is the inverse of f(x)=((2x+5))/((x-7)) ?
The inverse of f(x)=((2x+5))/((x-7)) is (5+7x)/(x-2)