What is the inverse of f(x)=5x^2-10x+7 ?

The inverse of f(x)=5x^2-10x+7 is (10+sqrt(20x-40))/(10),(10-sqrt(20x-40))/(10)

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inverse of f(x)=5x^2-10x+7

inverse

f (x) = 5 x^{2} - 10 x + 7

\frac{10 + 20 x - 40}{10}, \frac{10 - 20 x - 40}{10}

Solution steps

y = 5 x^{2} - 10 x + 7

Replace

x

with

y

x = 5 y^{2} - 10 y + 7

Solve for

y, x = 5 y^{2} - 10 y + 7

\frac{10 + 20 x - 40}{10}, \frac{10 - 20 x - 40}{10}

y = \frac{b x + 3}{3 x - 7}

f (x) = lo g_{10} (7 x)

f (x) = \frac{x ^{\frac{1}{3}}}{5} + 7

(x + 2)^{3} + 3

y = lo g_{\frac{3}{4}} (x)

What is the inverse of f(x)=5x^2-10x+7 ?
The inverse of f(x)=5x^2-10x+7 is (10+sqrt(20x-40))/(10),(10-sqrt(20x-40))/(10)