What is the inverse of f(x)=(x^{1/3})/5+7 ?

The inverse of f(x)=(x^{1/3})/5+7 is 125x^3-2625x^2+18375x-42875

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inverse of f(x)=(x^{1/3})/5+7

inverse

f (x) = \frac{x ^{\frac{1}{3}}}{5} + 7

125 x^{3} - 2625 x^{2} + 18375 x - 42875

Solution steps

y = \frac{x ^{\frac{1}{3}}}{5} + 7

Replace

x

with

y

x = \frac{y ^{\frac{1}{3}}}{5} + 7

Solve for

y, x = \frac{y ^{\frac{1}{3}}}{5} + 7

125 x^{3} - 2625 x^{2} + 18375 x - 42875

(x + 2)^{3} + 3

y = lo g_{\frac{3}{4}} (x)

\frac{x + 1}{x - 5}

f (x) = (x - 4)^{2} + 7

3 sin (2 x)

What is the inverse of f(x)=(x^{1/3})/5+7 ?
The inverse of f(x)=(x^{1/3})/5+7 is 125x^3-2625x^2+18375x-42875