What is the inverse of f(x)=8x-x^2 ?

The inverse of f(x)=8x-x^2 is 4-sqrt(-x+16),sqrt(-x+16)+4

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inverse of f(x)=8x-x^2

inverse

f (x) = 8 x - x^{2}

4 - - x + 16, - x + 16 + 4

Solution steps

y = 8 x - x^{2}

Replace

x

with

y

x = 8 y - y^{2}

Solve for

y, x = 8 y - y^{2}

4 - - x + 16, - x + 16 + 4

f (x) = ln (y)

f (x) = x + 1 - 6

f (x) = 2 (x - 2)^{2} + 1

ln (6 - 2 X)

f (x) = (\frac{3}{4})^{2 x}

What is the inverse of f(x)=8x-x^2 ?
The inverse of f(x)=8x-x^2 is 4-sqrt(-x+16),sqrt(-x+16)+4