What is the inverse of f(x)=4x^2+12+8 ?

The inverse of f(x)=4x^2+12+8 is (sqrt(x-20))/2 ,-(sqrt(x-20))/2

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inverse of f(x)=4x^2+12+8

inverse

f (x) = 4 x^{2} + 12 + 8

\frac{x - 20}{2}, - \frac{x - 20}{2}

Solution steps

y = 4 x^{2} + 12 + 8

Replace

x

with

y

x = 4 y^{2} + 12 + 8

Solve for

y, x = 4 y^{2} + 12 + 8

\frac{x - 20}{2}, - \frac{x - 20}{2}

50

f (x) = (0.2)^{- x} + 1

\frac{x + 1}{2 x}

7 x + 12

\frac{( 5 x - 3 )}{4 x + 5}

What is the inverse of f(x)=4x^2+12+8 ?
The inverse of f(x)=4x^2+12+8 is (sqrt(x-20))/2 ,-(sqrt(x-20))/2