What is the inverse of y=(x-1)/(sqrt(x-2)) ?

The inverse of y=(x-1)/(sqrt(x-2)) is (2+x^2+xsqrt(x^2-4))/2 ,(2+x^2-xsqrt(x^2-4))/2

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inverse of y=(x-1)/(sqrt(x-2))

inverse

y = \frac{x - 1}{x - 2}

\frac{2 + x ^{2} + x x ^{2} - 4}{2}, \frac{2 + x ^{2} - x x ^{2} - 4}{2}

Solution steps

y = \frac{x - 1}{x - 2}

Replace

x

with

y

x = \frac{y - 1}{y - 2}

Solve for

y, x = \frac{y - 1}{y - 2}

\frac{2 + x ^{2} + x x ^{2} - 4}{2}, \frac{2 + x ^{2} - x x ^{2} - 4}{2}

f (x) = \frac{2 x - 5}{x + 5}

f (x) = 0.5 x - 16

f (t) = 30 - 30 e^{- l n (10) t}

y = - x^{2} + 1

1 + x + 6

What is the inverse of y=(x-1)/(sqrt(x-2)) ?
The inverse of y=(x-1)/(sqrt(x-2)) is (2+x^2+xsqrt(x^2-4))/2 ,(2+x^2-xsqrt(x^2-4))/2