What is the inverse of f(x)=x+sqrt(x+2),x>2 ?

The inverse of f(x)=x+sqrt(x+2),x>2 is (2x+1+sqrt(4x+9))/2 ,(2x+1-sqrt(4x+9))/2

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inverse of f(x)=x+sqrt(x+2),x>2

inverse

f (x) = x + x + 2, x > 2

\frac{2 x + 1 + 4 x + 9}{2}, \frac{2 x + 1 - 4 x + 9}{2}

Solution steps

y = x + x + 2

Replace

x

with

y

x = y + y + 2

Solve for

y, x = y + y + 2

\frac{2 x + 1 + 4 x + 9}{2}, \frac{2 x + 1 - 4 x + 9}{2}

g (x) = 3 x^{2} - 4

4 x + 16

f (x) = - 9 x - 6

f (x) = - \frac{1}{2} x + 6

f (x) = 2 x - 14

What is the inverse of f(x)=x+sqrt(x+2),x>2 ?
The inverse of f(x)=x+sqrt(x+2),x>2 is (2x+1+sqrt(4x+9))/2 ,(2x+1-sqrt(4x+9))/2