What is the inverse of-(1-2z^{-1})/(z^{-1)-2} ?

The inverse of-(1-2z^{-1})/(z^{-1)-2} is (2-z)/(-2z+1)

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inverse of-(1-2z^{-1})/(z^{-1)-2}

inverse

- \frac{1 - 2 z ^{- 1}}{z ^{- 1} - 2}

\frac{2 - z}{- 2 z + 1}

Solution steps

y = - \frac{1 - 2 z ^{- 1}}{z ^{- 1} - 2}

Replace

z

with

y

z = - \frac{1 - 2 y ^{- 1}}{y ^{- 1} - 2}

Solve for

y, z = - \frac{1 - 2 y ^{- 1}}{y ^{- 1} - 2}

\frac{2 - z}{- 2 z + 1}

f (x) = \frac{3}{6 + 4 ^{x + 1}}

f (x) = 2 \frac{1}{3} x + 1

ln (2 x - 3)

f (x) = 3 - e^{- 2 x}

f (x) = \frac{7 x}{5 x - 2}

What is the inverse of-(1-2z^{-1})/(z^{-1)-2} ?
The inverse of-(1-2z^{-1})/(z^{-1)-2} is (2-z)/(-2z+1)