What is the inverse of h(x)=(x+3)^2-2,x<=-3 ?

The inverse of h(x)=(x+3)^2-2,x<=-3 is sqrt(x+2)-3,-sqrt(x+2)-3

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inverse of h(x)=(x+3)^2-2,x<=-3

inverse

h (x) = (x + 3)^{2} - 2, x \leq - 3

x + 2 - 3, - x + 2 - 3

Solution steps

y = (x + 3)^{2} - 2

Replace

x

with

y

x = (y + 3)^{2} - 2

Solve for

y, x = (y + 3)^{2} - 2

x + 2 - 3, - x + 2 - 3

f (x) = 100 (1 - \frac{t}{50})^{2}

f (x) = \frac{9 x + 3}{2}

f (x) = \frac{7 x}{x + 5}

f (x) = 4 + 6 + 11 x

f (x) = 2 - lo g_{9} (x)

What is the inverse of h(x)=(x+3)^2-2,x<=-3 ?
The inverse of h(x)=(x+3)^2-2,x<=-3 is sqrt(x+2)-3,-sqrt(x+2)-3