What is the inverse of f(x)=3-3sqrt(x),x>= 0 ?

The inverse of f(x)=3-3sqrt(x),x>= 0 is (x^2)/9-(2x)/3+1

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inverse of f(x)=3-3sqrt(x),x>= 0

inverse

f (x) = 3 - 3 x, x \geq 0

\frac{x ^{2}}{9} - \frac{2 x}{3} + 1

Solution steps

y = 3 - 3 x

Replace

x

with

y

x = 3 - 3 y

Solve for

y, x = 3 - 3 y

\frac{x ^{2}}{9} - \frac{2 x}{3} + 1

f (x) = lo g_{2} (3 x + 4) - 5

f (x) = \frac{4 - x}{x}

f (x) = 7 x^{2} - 2

f (x) = \frac{5}{9} (x - 32) + 273.15

f (x) = \frac{( 2 x + 5 )}{( x + 7 )}

What is the inverse of f(x)=3-3sqrt(x),x>= 0 ?
The inverse of f(x)=3-3sqrt(x),x>= 0 is (x^2)/9-(2x)/3+1