What is the inverse of f(x)=2x^2+4x-3 ?

The inverse of f(x)=2x^2+4x-3 is (-4+sqrt(8x+40))/4 ,(-4-sqrt(8x+40))/4

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inverse of f(x)=2x^2+4x-3

inverse

f (x) = 2 x^{2} + 4 x - 3

\frac{- 4 + 8 x + 40}{4}, \frac{- 4 - 8 x + 40}{4}

Solution steps

y = 2 x^{2} + 4 x - 3

Replace

x

with

y

x = 2 y^{2} + 4 y - 3

Solve for

y, x = 2 y^{2} + 4 y - 3

\frac{- 4 + 8 x + 40}{4}, \frac{- 4 - 8 x + 40}{4}

f (x) = 15 (x - 1) + \frac{1}{2}

f (x) = 1 - 2 - x

f (x) = \frac{4}{x - 2} + 3

f (x) = \frac{4}{x - 2} - 1

f (x) = 4 x^{2} + 5

What is the inverse of f(x)=2x^2+4x-3 ?
The inverse of f(x)=2x^2+4x-3 is (-4+sqrt(8x+40))/4 ,(-4-sqrt(8x+40))/4