What is the inverse of g(x)=\sqrt[3]{(x-1)/2} ?

The inverse of g(x)=\sqrt[3]{(x-1)/2} is 2x^3+1

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inverse of g(x)=\sqrt[3]{(x-1)/2}

inverse

2 x^{3} + 1

Solution steps

Replace

x

with

y

Solve for

2 x^{3} + 1

4 x^{3} - 41

f (x) = x^{5} - 7

f (x) = \frac{( x + 4 )}{( 2 x - 5 )}

f (x) = \frac{3 x}{7 x - 3}

f (x) = \frac{x ^{\frac{1}{3}} + 10}{3}

What is the inverse of g(x)=\sqrt[3]{(x-1)/2} ?
The inverse of g(x)=\sqrt[3]{(x-1)/2} is 2x^3+1