What is the inverse of f(x)=((x+2)^3-8)/5 ?

The inverse of f(x)=((x+2)^3-8)/5 is \sqrt[3]{5x+8}-2

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inverse of f(x)=((x+2)^3-8)/5

inverse

f (x) = \frac{( x + 2 ) ^{3} - 8}{5}

Solution steps

y = \frac{( x + 2 ) ^{3} - 8}{5}

Replace

x

with

y

x = \frac{( y + 2 ) ^{3} - 8}{5}

Solve for

y, x = \frac{( y + 2 ) ^{3} - 8}{5}

f (x) = 4 - x + 5

f (y) = 2 x - 3

\frac{1}{( z - \frac{1}{2} ) ( z - \frac{1}{4} )}

f (x) = \frac{x + 2}{x + 1}

ln (2 + e^{x - 3})

What is the inverse of f(x)=((x+2)^3-8)/5 ?
The inverse of f(x)=((x+2)^3-8)/5 is \sqrt[3]{5x+8}-2