What is the inverse of sqrt(x^2+6x) ?

The inverse of sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3

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inverse of sqrt(x^2+6x)

inverse

x^{2} + 6 x

- 3 + x^{2} + 9, - x^{2} + 9 - 3

Solution steps

y = x^{2} + 6 x

Replace

x

with

y

x = y^{2} + 6 y

Solve for

y, x = y^{2} + 6 y

- 3 + x^{2} + 9, - x^{2} + 9 - 3

f (x) = 2 2 x

g (x) = - 10 x + 5

\frac{2 - x}{x + 3}

f (x) = - 3 (x + 2)^{2} + 4

- \frac{1}{4}

What is the inverse of sqrt(x^2+6x) ?
The inverse of sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3