What is the inverse of f(x)=-3(x+2)^2+4 ?

The inverse of f(x)=-3(x+2)^2+4 is sqrt(-(x-4)/3)-2,-sqrt(-(x-4)/3)-2

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inverse of f(x)=-3(x+2)^2+4

inverse

f (x) = - 3 (x + 2)^{2} + 4

- \frac{x - 4}{3} - 2, - - \frac{x - 4}{3} - 2

Solution steps

y = - 3 (x + 2)^{2} + 4

Replace

x

with

y

x = - 3 (y + 2)^{2} + 4

Solve for

y, x = - 3 (y + 2)^{2} + 4

- \frac{x - 4}{3} - 2, - - \frac{x - 4}{3} - 2

- \frac{1}{4}

f (x) = \frac{1}{2} x^{2} - 4 x + 11

f (x) = 2 cos (3 x - 5) - 4

f (7) = 2 (x - 1)

f (x) = (5) (2^{(1 - x)})

What is the inverse of f(x)=-3(x+2)^2+4 ?
The inverse of f(x)=-3(x+2)^2+4 is sqrt(-(x-4)/3)-2,-sqrt(-(x-4)/3)-2