What is the inverse of f(x)= 1/2 x^2-4x+11 ?

The inverse of f(x)= 1/2 x^2-4x+11 is (8+sqrt(8x-24))/2 ,(8-sqrt(8x-24))/2

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inverse of f(x)= 1/2 x^2-4x+11

inverse

f (x) = \frac{1}{2} x^{2} - 4 x + 11

\frac{8 + 8 x - 24}{2}, \frac{8 - 8 x - 24}{2}

Solution steps

y = \frac{1}{2} x^{2} - 4 x + 11

Replace

x

with

y

x = \frac{1}{2} y^{2} - 4 y + 11

Solve for

y, x = \frac{1}{2} y^{2} - 4 y + 11

\frac{8 + 8 x - 24}{2}, \frac{8 - 8 x - 24}{2}

f (x) = 2 cos (3 x - 5) - 4

f (7) = 2 (x - 1)

f (x) = (5) (2^{(1 - x)})

\frac{3}{2} x + 12

f (x) = \frac{x + 1}{x + 10}

What is the inverse of f(x)= 1/2 x^2-4x+11 ?
The inverse of f(x)= 1/2 x^2-4x+11 is (8+sqrt(8x-24))/2 ,(8-sqrt(8x-24))/2