What is the inverse of f(x)=(x+1)/(x+10) ?

The inverse of f(x)=(x+1)/(x+10) is (1-10x)/(x-1)

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inverse of f(x)=(x+1)/(x+10)

inverse

f (x) = \frac{x + 1}{x + 10}

\frac{1 - 10 x}{x - 1}

Solution steps

y = \frac{x + 1}{x + 10}

Replace

x

with

y

x = \frac{y + 1}{y + 10}

Solve for

y, x = \frac{y + 1}{y + 10}

\frac{1 - 10 x}{x - 1}

ln (4)

\frac{x}{2} x + 3

f (x) = x^{2} - 2 x

f (x) = 300 (1 + \frac{0.05}{12})^{12 x}

f (x) = 3 + \frac{1}{x - 1}

What is the inverse of f(x)=(x+1)/(x+10) ?
The inverse of f(x)=(x+1)/(x+10) is (1-10x)/(x-1)