What is the inverse of f(x)=sqrt(x^2-2x) ?

The inverse of f(x)=sqrt(x^2-2x) is 1+sqrt(x^2+1),1-sqrt(x^2+1)

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inverse of f(x)=sqrt(x^2-2x)

inverse

f (x) = x^{2} - 2 x

1 + x^{2} + 1, 1 - x^{2} + 1

Solution steps

y = x^{2} - 2 x

Replace

x

with

y

x = y^{2} - 2 y

Solve for

y, x = y^{2} - 2 y

1 + x^{2} + 1, 1 - x^{2} + 1

f (x) = 300 (1 + \frac{0.05}{12})^{12 x}

f (x) = 3 + \frac{1}{x - 1}

f (x) = 6^{x} + 5

y = - x^{2} + 10

What is the inverse of f(x)=sqrt(x^2-2x) ?
The inverse of f(x)=sqrt(x^2-2x) is 1+sqrt(x^2+1),1-sqrt(x^2+1)