What is the inverse of f(x)=(4x-3)/(3x+1) ?

The inverse of f(x)=(4x-3)/(3x+1) is (-3-x)/(3x-4)

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inverse of f(x)=(4x-3)/(3x+1)

inverse

f (x) = \frac{4 x - 3}{3 x + 1}

\frac{- 3 - x}{3 x - 4}

Solution steps

y = \frac{4 x - 3}{3 x + 1}

Replace

x

with

y

x = \frac{4 y - 3}{3 y + 1}

Solve for

y, x = \frac{4 y - 3}{3 y + 1}

\frac{- 3 - x}{3 x - 4}

x^{2} + 16

\frac{3}{5} x - 9

(4 x)^{- \frac{2}{5}}

3 x^{2} - 5

3 x^{2} - 7

What is the inverse of f(x)=(4x-3)/(3x+1) ?
The inverse of f(x)=(4x-3)/(3x+1) is (-3-x)/(3x-4)